CODEWITHSUNDEEP
javascriptstring
c1ic
c1ic

Reputation: 21

Using the Includes method on a string with multiple values

I want to check if a string has any of the following words, apple, pear, orange and if it does, do some code. However my code only currently checks for the first word, apple and not the other 2. Fruit variable gets sent from a client side. 

var fruit = fruit;

if (fruit.includes(["apple", "pear", "orange"])
{ 
    //do some code
}

I tried | instead of a comma

I need it so it checks all for all of the words, not just the first

Upvotes: 2

Views: 1631

Answers (4)

zer00ne
zer00ne

Reputation: 43910

.includes() returns a Boolean (true/false) and it appears that you want the actual matches to return instead. .find() returns the match but like .include() it stops after the first match so you'll need to iterate through the search keys.

The following demo runs .filter() through the array to be searched (primary). .filter() will return the current value that's evaluated as true. By running .includes() on the search array (search) inside the .filter() you can search each element of array primary.

const primary = ['alpha', 'beta', 'gamma', 'delta', 'epsilon'];
const search = ['beta', 'delta', 'omega'];

const matches = (array1, array2) => array1.filter(word => array2.includes(word));

console.log(matches(primary, search));

Upvotes: 1

Cuong Le Ngoc
Cuong Le Ngoc

Reputation: 11975

You can use regex instead of includes() with a loop to solve it.

Demo:

var fruit = "green dpear";

if (/\b(apple|pear|orange)\b/.test(fruit)) {
  console.log('match');
} else {
  console.log('not_match');
}

Upvotes: 1

Akhilesh
Akhilesh

Reputation: 968

you can use forEach loop

const fruit = ['apple', 'orange'];

fruit.forEach( function(v, i) {
    if ( fruit[i].includes('orange') ) {
    // do you stuff
  }
});

Upvotes: 0

Mureinik
Mureinik

Reputation: 311393

You could use the some method:

if (["apple", "pear", "orange"].some(x => fruit.includes(x))) {
    // Do something...

Upvotes: 3

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