CODEWITHSUNDEEP
python
vijay manideep
vijay manideep

Reputation: 1

how to print list elements as shown in above

i need to access first element of nested lists and print it and also need to access second elements of every list and print it

details = {"name":["suresh","ramesh"],"age":[25,26],"city":["hyd","chn"]}

# print(" my name is {}, and age is {} and coming from {}".format())

required output:

# my name is suresh, age is 25 and coming from hyd
# my name is ramesh, age is 26 and coming from chn

unable to write

Upvotes: 0

Views: 54

Answers (2)

Anshul
Anshul

Reputation: 1669

I took the Reference from Andrej's answer and here is modified code

details = {"name":["suresh","ramesh"],"age":[25,26],"city":["hyd","chn"]}

s = "my name is {}, and age is {} and coming from {}"

print(*map(lambda detail: s.format(*detail) , zip(*details.values())) , sep ='\n' )

This returns the expected output

my name is suresh, and age is 25 and coming from hyd
my name is ramesh, and age is 26 and coming from chn

Upvotes: 0

Andrej Kesely
Andrej Kesely

Reputation: 195613

You can use zip() method with dict.values():

details = {"name":["suresh","ramesh"],"age":[25,26],"city":["hyd","chn"]}

s = "my name is {}, and age is {} and coming from {}"

for detail in zip(*details.values()):
    print(s.format(*detail))

Prints:

my name is suresh, and age is 25 and coming from hyd
my name is ramesh, and age is 26 and coming from chn

EDIT: It's better to see what each step is doing:

dict.values() holds:

dict_values([['suresh', 'ramesh'], [25, 26], ['hyd', 'chn']])

[*zip(*details.values())] holds:

[('suresh', 25, 'hyd'), ('ramesh', 26, 'chn')]

Upvotes: 3

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