CODEWITHSUNDEEP
javascriptregex
Mohan Raj
Mohan Raj

Reputation: 457

Replace all the matching query parameter value in the URL in Javascript

I have the below Path/URL 

test = "/test/test-products/?pId=9401100&imgId=14607518&catID=5449&modelId=pros&cm_sp=XIT_resp-_-PR-_-14607518_9401100&lid=xit-test-14607518-9401100";

newPath = test.replace('14607518', '12345678');

Not updating every occurrences of the matching string though it has hypen,underscore(-_-)

How can I replace all occurrences of 14607518 with regex?

Upvotes: 0

Views: 59

Answers (3)

MonkeyZeus
MonkeyZeus

Reputation: 20737

You should use:

([^\d])(14607518)([^\d])

because it will help you to avoid accidentally targeting numbers such as 146075189

const regex = /([^\d])(14607518)([^\d])/gm;
const str = `/test/test-products/?pId=9401100&imgId=146075189&catID=5449&modelId=pros&cm_sp=XIT_resp-_-PR-_-14607518_9401100&lid=xit-test-14607518-9401100`;
const subst = `$112345678$3`;

// The substituted value will be contained in the result variable
const result = str.replace(regex, subst);

See https://regex101.com/r/0pJWwo/1

Upvotes: 0

Code Maniac
Code Maniac

Reputation: 37755

When you pass a string instead of regex object to replace it just replaces the first occurrence only, You need to use a g tag and regex pattern to replace all the instances

const test = "/test/test-products/?pId=9401100&imgId=14607518&catID=5449&modelId=pros&cm_sp=XIT_resp-_-PR-_-14607518_9401100&lid=xit-test-14607518-9401100";

const newPath = test.replace(/14607518/g, '12345678');

console.log(newPath)

Upvotes: 1

Michael
Michael

Reputation: 591

The syntax is a bit different since you're using regex here.

test.replace(/14607518/g, '12345678');

Instead of 

test.replace('14607518', '12345678');

Where the 'g' at the end means 'global', or replace all occurrences.

Upvotes: 1

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