Reputation: 1168
I have a dataframe from which I want to select data between a range, only the first occurrence of this range.
The dataframe:
data = {'x':[1,2,3,4,5,6,7,6.5,5.5,4.5,3.5,2.5,1], 'y':[1,4,3,3,52,3,74,64,15,41,31,12,11]}
df = pd.DataFrame(data)
eg: select x from 2 to 6, first occurarence:
x y
0 1.0 1 #out of range
1 2.0 4 #out of range
2 3.0 3 #this first occurrence
3 4.0 3 #this first occurrence
4 5.0 52 #thisfirst occurrence
5 6.0 3 #out of range
6 7.0 74 #out of range
7 6.5 64 #out of range
8 5.5 15 #not this since repeating RANGE
9 4.5 41 #not this since repeating RANGE
10 3.5 31 #not this since repeating RANGE
11 2.5 12 #not this since repeating RANGE
12 1.0 11 #out of range
Output
x y
2 3.0 3 #this first occurrence
3 4.0 3 #this first occurrence
4 5.0 52 #thisfirst occurrence
I am trying to modify this example: Select DataFrame rows between two dates to select data between 2 values for their first occurrence:
xlim=[2,6]
mask = (df['x'] > xlim[0]) & (df['x'] <= xlim[1])
df=df.loc[mask] #need to make it the first occurrence here
Upvotes: 2
Views: 512
Reputation: 88276
Here's one approach:
# mask with True whenever a value is within the range
m = df.x.between(2,6, inclusive=False)
# logical XOR with the next row and cumsum
# Keeping only 1s will result in the dataframe of interest
df.loc[(m ^ m.shift()).cumsum().eq(1)]
x y
2 3.0 3
3 4.0 3
4 5.0 52
Details -
df.assign(in_range=m, is_next_different=(m ^ m.shift()).cumsum())
x y in_range is_next_different
0 1.0 1 False 0
1 2.0 4 False 0
2 3.0 3 True 1
3 4.0 3 True 1
4 5.0 52 True 1
5 6.0 3 False 2
6 7.0 74 False 2
7 6.5 64 False 2
8 5.5 15 True 3
9 4.5 41 True 3
10 3.5 31 True 3
11 2.5 12 True 3
12 1.0 11 False 4
Upvotes: 3