CODEWITHSUNDEEP
javaregex
s shah
s shah

Reputation: 21

Removing Decimals inside a string

I am trying to add all the values to a string builder so i can serialize it. So, my stringbuilder looks like

sb = abc78.00xyz

Now, here i want to just remove the 0's after the decimal and want output like

Input       ->  Output I want
abc78.00xyz -> abc78xyz
abc78.08xyz -> abc78.08xyz

I tried using regex but it doesnt work Tried : 

sb.toString().replaceAll("\\.0*$", "")
sb.toString().replaceAll("[.0]+", "")

but this only works if i have numbers.

Can someone tell me how i can get the desired values ?

Upvotes: 1

Views: 76

Answers (1)

Wiktor Stribiżew
Wiktor Stribiżew

Reputation: 626754

You may use

s = s.replaceAll("(?<=\\d)\\.0+(?!\\d)", "");

See the regex demo

Details

  • (?<=\d) - right before the current location, there must be a digit
  • \. - a dot
  • 0+ - one or more 0 digits
  • (?!\d) - not followed with any other digit.

Java demo:

List<String> strs = Arrays.asList("abc78.00xyz", "abc78.08xyz");
for (String str : strs) {
    System.out.println( str.replaceAll("(?<=\\d)\\.0+(?!\\d)", "") );
}
// => abc78xyz, abc78.08xyz

Upvotes: 1

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