CODEWITHSUNDEEP
javaregexstring
Cody
Cody

Reputation: 8944

Remove trailing decimal point & zeroes with Regex

Is this the proper REGEX to remove trailing decimal and zeroes from a string? I can't get it to work. What am I missing?

  1. 78.000 -> 78
  2. 78.008 -> 78.008

str.replaceAll("^.0*$", "");

Upvotes: 15

Views: 41017

Answers (3)

Håvard
Håvard

Reputation: 10080

You need to escape the ., as it is a special character in Regex that matches any character. You also have to remove the ^, which anchors at the beginning of the number.

str.replaceAll("\\.0*$", "");

You can use a lookbehind if you want to make sure there is a number in front of the dot, like this:

str.replaceAll("(?<=^\\d+)\\.0*$", "");

The lookbehind (the (?<=...) part) is not a part of the match, so it will not be replaced, but it still has to match for the rest of the regex to match.

Upvotes: 25

NullUserException
NullUserException

Reputation: 85458

Get rid of the ^, which matches the start of the string. You also need to escape ., since it's a regex meta character that matches any character (except newlines):

str.replaceAll("\\.0*$", "");

Demo: http://ideone.com/RSJrO

Upvotes: 4

Joseph Silber
Joseph Silber

Reputation: 219930

Nope. Use this:

str.replaceAll("[.0]+$", "");

Upvotes: 5

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