CODEWITHSUNDEEP
pythonstringformatpercentage
Raubtier
Raubtier

Reputation: 362

Python format string for percentage with space before %

I'd like to format a number as percentage, i.e. 0.331 -> '33.1 %'.

The obvious way in simple code is to use '{:.1f} %'.format(percentage*100) Since I am only passing the format string to a function as in fn(dataframe, format='{:.1f}'), I cannot easily multiply the data with 100 (since data is used for calculations inside the function as well). Now Python has the % format specifier which almost does what I want: '{:.1%}'.format(0.331) gives '33.1%', but I want '33.1 %' (as required by DIN 5008)

Is there a way to use insert the space between the number and percent symbol using the format string? So basically like '{:6.1%}'.format(0.331) but with the space on the other side of the number.

If that's not possible, I have to crack open the function the format string is passed to. And that seems a hacky solution that I'd like to avoid.

Upvotes: 2

Views: 3324

Answers (3)

oppressionslayer
oppressionslayer

Reputation: 7224

You can use f'' strings:

num = .331 
print(f'the percent is {num*100:6.2f} %')

percent is  33.10 %

https://realpython.com/python-f-strings/

Upvotes: 1

Uber
Uber

Reputation: 368

To be honest as a lazy programmer myself I would just use str.replace (https://docs.python.org/3/library/stdtypes.html#str.replace) after the formatting appended like this:

a = '{:.1%}'.format(0.331).replace('%', ' %')
print(a)

gives: 33.1 %

Upvotes: 2

Greg
Greg

Reputation: 51

Have you checked how to use f-strings?

number_1 = 0.331

string_1 = f'{number_1 * 100} %'

print(string_1)

output: 33.1 %

Upvotes: 0

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