CODEWITHSUNDEEP
javaregex
Kyle
Kyle

Reputation: 3042

How can I use a regex expression to look for a particular URL?

I connected to a site using URLConnection and the result I'm looking for is the url inside these parenthesis: callback_request("https://secure.runescape.com/m=displaynames/s=bOVZmsrjbNQzntbDei*324JUo*3ozJ7hR*h1KNlxc6kPaBeKCBrdKIxD*edhi4qH/check_name.ws?displayname=" + escape(text), handleResult);

The problem I'm having is the : s=bOVZmsrjbNQzntbDei*324JUo*3ozJ7hR*h1KNlxc6kPaBeKCBrdKIxD*edhi4qH is random each time--it's the session.

How can I use a regex expression to scan the page and look for https://secure.runescape.com/m=displaynames/(random_session_id)/check_name.ws?displayname=?

Upvotes: 0

Views: 129

Answers (3)

manojlds
manojlds

Reputation: 301527

Something like:

"https://secure\.runescape\.com/m=displaynames/s=[a-zA-Z1-9*]+/check_name\.ws\?displayname="

Upvotes: 1

Favonius
Favonius

Reputation: 13984

Try this:

import java.util.regex.Pattern;

public class Regex {
    public static void main(String[] args) 
    {
        Pattern p = Pattern.compile("https://secure\\.runescape\\.com/m=displaynames/.*/check_name\\.ws\\?displayname=\\?");
        System.out.println(p.matcher("https://secure.runescape.com/m=displaynames/s=bOVZmsrjbNQzntbDei*324JUo*3ozJ7hR*h1KNlxc6kPaBeKCBrdKIxD*edhi4qH/check_name.ws?displayname=?").find());
    }
}

Upvotes: 1

Peter Lawrey
Peter Lawrey

Reputation: 533870

If you know displayname will be last you can 

String displayName = url.split("displayname=")[1];

Upvotes: 1

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