Reputation: 14615
I am trying to make a change to all items of a GridView
.
I have tried to iterate through either the model or the grid, I looked at similar examples on the web, but everything I try ends with Cannot read property 'buttonText' of undefined
.
It seems to me that the problem is that the interpreter can't figure out that the item from the grid or model is a Button
. But I don't know how to cast it.
If I change the log to only display the item, not any property, (see code snippet), it seems that it knows it is an item... see my experiments below.
The only thing I can make work is set a property (or call a signal, or a function) from the delegate. But that only affects one grid item, not all.
How can I set a property on every item of the grid ? Alternatively, how can I send a signal, or call a function, on every item?
My experiments are in function changeEverythingFunction()
file: Button.qml
Item
{
id: itemButton
signal changeEverything
property int buttonIndex
property string buttonText
...
}
file: Model.qml
Item
{
id: modelItem
ListModel
{
id: listModel
}
property int buttonCount: listModel.count
function changeEverythingFunction()
{
// for (var i = 0; i < buttonCount; i++)
// listModel.setProperty(i, buttonText, "abc")
for(var childIndex in gridItems.contentItem.children)
{
console.log(listModel.get(childIndex).buttonText) // Cannot read property 'buttonText' of undefined
console.log(gridItems.contentItem.children[childIndex].buttonText) // Cannot read property 'buttonText' of undefined
console.log(gridItems.contentItem.children[childIndex]["buttonText"]) // undefined (I saw this in a SO example)
var item = gridItems.contentItem.children[childIndex]
console.log(item) // qml: QQuickItem(0xe496370)
}
}
MouseArea
{
....
Rectangle
{
...
GridView
{
id: gridItems
anchors.fill: parent
clip: true
model: listModel
delegate: Item
{
id: buttonDelegate
Button
{
buttonIndex: gridId
buttonText: itemText
onChangeEverything:
{
changeEverythingFunction();
}
}
}
}
}
}
}
Upvotes: 1
Views: 1552
Reputation: 243955
Your approach is in the opposite direction: Your approach is to obtain the item of the view and modify it, but the approach that Qt points out is that the view reflects the information of the model and modifies it when necessary.
The following is a simple example where every time you press on the button with "change me" text increasing the number it shows, but if you press the button with "change all" text it will change all the numbers. As it is observed everything is done through the model, not through the view that are only used to display information or receive user interaction.
import QtQuick 2.14
import QtQuick.Window 2.14
import QtQuick.Controls 2.14
import QtQuick.Layouts 1.14
Window {
visible: true
width: 640
height: 480
ListModel{
id: listmodel
}
function changeAll(){
for(var i=0; i< listmodel.count; ++i){
listmodel.setProperty(i, "number", listmodel.get(i).number + 1)
}
}
GridView{
id: grid
anchors.fill: parent
clip: true
model: listmodel
cellHeight: 120
cellWidth: 120
delegate: Item {
width: grid.cellWidth; height: grid.cellHeight
Column {
anchors.fill: parent
Text { text: model.number; anchors.horizontalCenter: parent.horizontalCenter }
Button{text: "change me"; onClicked: model.number +=1}
Button{text: "change all"; onClicked: changeAll()}
}
}
}
Component.onCompleted: {
for(var i=0; i < 10; ++i){
listmodel.append({"number": 0});
}
}
}
Upvotes: 1