Reputation: 1
I have a dataset (loadings from an efa) with three variables/factors (ML1, ML2, ML3) and I would like to extract the names of cases that have an absolute value of >= 0.3 for exactly one variable/factor.
This is what I worked out so far:
items <- row.names(loadings1[(abs(loadings1$ML1) >= 0.3 | abs(loadings1$ML2) >= 0.3 | abs(loadings1$ML3) >= 0.3) & sum(abs(loadings1$ML1) >= 0.3 , abs(loadings1$ML2) >= 0.3 , abs(loadings1$ML3) >= 0.3 ) == 1,])
It only returns an empty character and I know that it is not because there are no cases that match my criteria.
I also tried:
row.names(loadings1[abs(loadings1$ML1) >= 0.3 | abs(loadings1$ML2) >= 0.3 | abs(loadings1$ML3) >= 0.3 & sum(abs(loadings1$ML1) >= 0.3 , abs(loadings1$ML2) >= 0.3 , abs(loadings1$ML3) >= 0.3 ) == 1,])
The second attempt seemed to ignore the & condition entirely even though the different or conditions worked.
I also found this for help and didn't really see why it wouldn't work in my case.
Any ideas?
Upvotes: 0
Views: 59
Reputation: 39707
You can use rowSums
to find rows where exactly one variable is >= 0.3
.
items <- row.names(loadings1)[rowSums(abs(loadings1[c("ML1","ML2","ML3")]) >= 0.3) == 1]
items
#[1] "6" "7"
Data:
set.seed(1)
(loadings1 <- data.frame(id = 1:10, ML1 = rnorm(10), ML2 = rnorm(10), ML3 = rnorm(10)))
# id ML1 ML2 ML3
#1 1 -0.6264538 1.51178117 0.91897737
#2 2 0.1836433 0.38984324 0.78213630
#3 3 -0.8356286 -0.62124058 0.07456498
#4 4 1.5952808 -2.21469989 -1.98935170
#5 5 0.3295078 1.12493092 0.61982575
#6 6 -0.8204684 -0.04493361 -0.05612874
#7 7 0.4874291 -0.01619026 -0.15579551
#8 8 0.7383247 0.94383621 -1.47075238
#9 9 0.5757814 0.82122120 -0.47815006
#10 10 -0.3053884 0.59390132 0.41794156
Upvotes: 2
Reputation: 83
Using a dplyr
method, you can do it this way. case_when
is useful when applying multiple conditions.
set.seed(1)
df <- tibble(id = 1:10, ML1 = rnorm(10), ML2 = rnorm(10), ML3 = rnorm(10))
df %>%
mutate(
Which = case_when(
abs(ML1) >= 0.3 & abs(ML2) < 0.3 & abs(ML3) < 0.3 ~ "ML1",
abs(ML2) >= 0.3 & abs(ML1) < 0.3 & abs(ML3) < 0.3 ~ "ML2",
abs(ML3) >= 0.3 & abs(ML1) < 0.3 & abs(ML2) < 0.3 ~ "ML3",
)
) %>%
filter(!is.na(Which)) %>%
select(id) %>%
unlist
This prints a list of the ids which qualify. You could also leave it as a data frame and get more information, such as which ML column was >= 0.3.
Edit: Forgot absolute value. Also, Using your method would work, but you have to use parentheses around each condition such as (cond1 & !cond2 & !cond3) | (!cond1 & cond2 & !cond3).
Upvotes: 1