Reputation: 57
I'm doing a doubly linked list with a sentinel node that makes the doubly linked list a circular list (there is no head and no tail pointers to the front and back, instead head is referred to by m_sentinel->m_next and tail is referred to by m_sentinel->m_prev). Here is the following code:
In MyList.h:
template <typename T>
class Node
{
public:
T m_element;
Node<T> *m_prev;
Node<T> *m_next;
// Helps make a dummy/sentinel/junk node
Node(Node<T> *in_prev, Node<T> *in_next):
m_prev(in_prev), m_next(in_next){}
Node(const T &x, Node<T> *in_prev, Node<T> *in_next):
m_element(x), m_prev(in_prev), m_next(in_next){}
};
template <typename T>
class MyList
{
private:
Node<T> *m_sentinel = nullptr;
int m_size;
public:
MyList();
~MyList();
MyList<T> & operator=(const MyList<T> &source);
void clear();
void push_back(const T &x);
In MyList.hpp:
template <typename T>
MyList<T>::MyList()
{
m_size = 0;
m_sentinel = new Node<T>(NULL, NULL);
}
template <typename T>
MyList<T>::~MyList()
{
clear();
m_size = 0;
}
template <typename T>
MyList<T> & MyList<T>::operator=(const MyList<T> &source)
{
if(this == &source)
{
return *this;
}
while(source.m_sentinel->m_next != source.m_sentinel)
{
Node<T> *temp = source.m_sentinel->m_next;
push_back(temp->m_element);
source.m_sentinel->m_next = temp->m_next;
}
return *this;
}
template <typename T>
void MyList<T>::clear()
{
if(m_sentinel->m_prev == NULL && m_sentinel->m_next == NULL)
{
delete m_sentinel;
}
else
{
int k = size();
for(int i = 0; i < k; i++)
{
pop_back();
}
delete m_sentinel;
}
}
template <typename T>
void MyList<T>::push_back(const T &x)
{
Node<T> *newNode;
newNode = new Node<T>(x, NULL, NULL);
if(m_sentinel->m_prev == NULL && m_sentinel->m_next == NULL)
{
newNode->m_prev = m_sentinel;
newNode->m_next = m_sentinel;
m_sentinel->m_prev = newNode;
m_sentinel->m_next = newNode;
}
else
{
newNode->m_next = m_sentinel;
newNode->m_prev = m_sentinel->m_prev;
Node<T> *temp = newNode->m_prev;
m_sentinel->m_prev = newNode;
temp->m_next = m_sentinel->m_prev;
}
m_size++;
}
In main.cpp:
#include "MyList.h"
int main()
{
MyList<int> x;
x.push_front(1);
x.push_front(2);
x.push_front(3);
x.push_front(4);
x.push_front(5);
x.push_front(6);
x.push_front(7);
MyList<int> p;
p = x;
// Below just outputs each linked list
int j = 0;
int m = x.size();
cout << endl << endl;
for(auto i = 0; i < m; i++)
{
cout << x.front() << endl;
x.pop_front();
j++;
}
cout << endl << endl;
j = 0;
m = p.size();
for(auto i = 0; i < m; i++)
{
cout << p.front() << endl;
p.pop_front();
j++;
}
cout << endl << endl;
When running this code, x does get copied to p successfully. When outputting p, the following output is given: 7 6 5 4 3 2 1, but when outputting x, the following output is given: -19823746 ... which is just junk memory values (which tells me x is being changed obviously, but p is successfully getting x's contents). I have no clue why it's changing; I'm looking for a fix/solution to the assignment operator because it's not working properly.
Upvotes: 1
Views: 359
Reputation: 96810
Inside of your MyList::operator=
you should be iterating with a new variable, not the source.m_sentinel
member itself. This changes the actual list and is actually removing nodes.
Use this instead:
Node<T>* current = source.m_sentinel;
while (current->m_next != source.m_sentinel) {
Node<T>* temp = current->m_next;
push_back(temp->m_element);
current = temp;
}
Upvotes: 1