CODEWITHSUNDEEP
pythonpython-3.xfilesavefile-handling
user8388729
user8388729

Reputation:

writing the output of print function to a textfile

I want to save ''contents'' to a new text file in python. I need to have all the words in lowercase to be able to find the word frequency. '''text.lower()''' didn't work. Here is the code;

text=open('page.txt', encoding='utf8')
for x in text:
print(x.lower())

I want to save the results of print to a new text file. How can I do that?

Upvotes: 1

Views: 67

Answers (3)

Ch3steR
Ch3steR

Reputation: 20689

You can use file parameter in print to directly print the output of print(...) to your desired file.

text=open('page.txt', encoding='utf8')
text1=open('page1.txt', mode='x',encoding='utf8') #New text file name it according to you
for x in text:
    print(x.lower(),file=text1)
text.close()
text1.close()

Note: Use with while operating on files. As you don't have to explicitly use .close it takes care of that.

Upvotes: 1

C.Nivs
C.Nivs

Reputation: 13126

You are opening the file page.txt for reading, but it's not open to write. Since you want to save to a new text file, you might also open new_page.txt where you write all of the lines in page.txt lowercased:


# the with statement is the more pythonic way to open a file
with open('page.txt') as fh:

    # open the new file handle in write mode ('w' is for write, 
    # it defaults to 'r' for read
    with open('new_page.txt', 'w') as outfile:
        for line in fh:
            # write the lowercased version of each line to the new file
            outfile.write(line.lower())

The important thing to note is that the with statement negates the need for you to close the file, even in the case of an error

Upvotes: 1

Arwen
Arwen

Reputation: 168

import sys 
stdoutOrigin=sys.stdout 
sys.stdout = open("yourfilename.txt", "w")
#Do whatever you need to write on the file here.
sys.stdout.close()
sys.stdout=stdoutOrigin

Upvotes: 0

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