CODEWITHSUNDEEP
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Julian05
Julian05

Reputation: 33

Using variables outside a function

I am currently writing my first script in Powershell and I am already facing the first problem. I would like to read the value from a variable in a function so that I can use this variable in another cmd-let later. The problem now is that the variable is only recognized inside the function block and not outside. How do I get this to work?

Thanks for the help :-)

function Write-Log([string]$logtext, [int]$level=0)
{
  if($level -eq 0)
{
    $logtext = "[INFO] " + $logtext
    $text = "["+$logdate+"] - " + $logtext
    Write-Host $text
}
}

Send-MailMessage -To "<[email protected]>" -Subject "$text" -Body "The GPO backup creation was completed with the following status: `n $text" -SmtpServer "[email protected]" -From "[email protected]"

I would like to submit $text

Upvotes: 3

Views: 3377

Answers (3)

Peter L
Peter L

Reputation: 3343

The old array trick
I ended up using an array to get around this problem:

$lastRun = @($null) # array so function can edit
function Delay() {
    if ($lastRun[0] -ne $null) {
        ...
    }

    $lastRun[0] = Get-Date
}

Upvotes: 0

Mathias R. Jessen
Mathias R. Jessen

Reputation: 174435

This has to do with variable scoping behavior in PowerShell.

By default, all variables in the caller's scope is visible inside the function. So we can do:

function Print-X
{
  Write-Host $X
}

$X = 123
Print-X # prints 123
$X = 456 
Print-X # prints 456

So far, so good. But when we start writing to variables outside the function itself, PowerShell transparently creates a new variable inside the function's own scope:

function Print-X2
{
  Write-Host $X   # will resolve the value of `$X` from outside the function
  $X = 999        # This creates a new `$X`, different from the one outside
  Write-Host $X   # will resolve the value of the new `$X` that new exists inside the function
}

$X = 123
Print-X2       # Prints 123, and 999
Write-Host $X  # But the value of `$X` outside is still 123, unchanged

So, what to do? You could use a scope modifier to write to the variable outside the function, but the real solution here is to return the value from the function instead:

function Write-Log([string]$logtext, [int]$level=0, [switch]$PassThru = $true)
{
    if($level -eq 0)
    {
        $logtext = "[INFO] " + $logtext
        $text = "["+$logdate+"] - " + $logtext
        Write-Host $text
        if($PassThru){
            return $text
        }
    }
}

$logLine = Write-Log "Some log message" -PassThru

Send-MailMessage -Subject $logLine ...

Upvotes: 5

Mohamed Shabeer kp
Mohamed Shabeer kp

Reputation: 882

if you need to access a variable outside a function in Powershell you might need to use the global variable.

$global:myglobalvariable="This is a PowerShell global variable"

or if its a null 

$global:myglobalvariable2 = $null

Upvotes: 2

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