CODEWITHSUNDEEP
pythonbitwise-and
Vishweswar Mohapatra
Vishweswar Mohapatra

Reputation: 1

Logic behind not getting output while using Bitwise AND instead of AND Operator

Can you give the clarity in Python

i = 2
if i<3 and i>1:
   print('its ok')

Output: 'its ok' ------> no problem over here

But when I'm going to use Bitwise AND instead of AND, the code has been executed but nothing in output.

i = 2
if i<3 & i>1:
   print('its ok')

Output: nothing ------> why ??

Upvotes: 0

Views: 50

Answers (3)

magikarp
magikarp

Reputation: 470

i<3 & 1>1 is read as i<(3 & i)>1. & is the bitwise AND operator.

So, this evaluates to i<(3 & 2)>1 which is equal to i<2>1 .
i ( = 2) is not less than 2, so the first condition is False. Therefore, it fails the condition.

Upvotes: 0

Diogenis Siganos
Diogenis Siganos

Reputation: 797

Bitwise operate on numbers, but they treat them as if they were a string of bits, written in binary.

a & b

The & operator returns 1 when the corresponding bits of both a and b are 1. Otherwise it returns 0.

If you use the && logical operator, it will work as you want it:

i = 2

if i < 3 && i > 1: 
    print('Works!')

Upvotes: 0

Ayush Pallav
Ayush Pallav

Reputation: 1057

You are trying to use bitwise AND (&) to perform logical AND (&&) operation!

It should be

if i<3 && i>1:
    print('its ok')

Upvotes: 2

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