Reputation: 4689
I can't believe I couldn't find an answer on this so please point me in the right direction if I am wrong.
I am trying to do something simple:
There's a function component from a library that I include.
I need to get a ref to it.
Crucially, React says this:
Ref forwarding lets components opt into exposing any child component’s ref as their own.
Unfortunately, this library component has not opted in using forwardRef
.
What is the correct approach to get a ref to this element?
The 3rd party library component in question looks like so (simplified):
function OutboundLink(props) {
return (
<a {...props}
...
/>
)
}
My component looks like so:
function MyComp(props) {
const ref = useRef(null)
return (
<OutboundLink ref={ref} {...props} >
{children}
</OutboundLink>
)
}
but I am greeted with the errors about not being able to pass refs to a function component. Normally I would wrap in forwardRef
, but can't in this case since I can't modify the library's code directly.
I did see this and this but didn't think either applied to me.
Any ideas?
Upvotes: 5
Views: 1377
Reputation: 187074
You can't directly. There's no hook to let you in if the component wasn't written that way.
I think your best bet would be to wrap the component, capture a ref, and then drill into its children with DOM methods.
const wrapperRef = useRef(null)
const innerRef = useRef(null)
useEffect(() => {
if (wrapperRef.current) {
innerRef.current = wrapperRef.current.querySelector('a')
// innerRef.current is now the first <a> tag inside <OutboundLink>
}
})
return <div>
<div ref={wrapperRef}>
<OutboundLink {...props}>
{children}
</OutboundLink>
</div>
</div>
Codepen example (view the console)
But really, this is a bit of a hack. You should use a component that handles this better. Look into how hard it would be to write this component yourself from scratch. It may be trivial, and worth it.
Upvotes: 6