CODEWITHSUNDEEP
swiftgenericsenumsparametersfunc
Confused
Confused

Reputation: 3926

Passing various enum case as function param in Swift

I have two simple enums like this:

    enum Bar:String {
        case obj1 = "Object1"
    }

    enum Foo:String {
        case obj2 = "Object2"
    }

I want to write a function that takes enum case as param and it should print the case raw value. Something like this:

printCase(Bar.obj1) // prints "Object1"
printCase(Foo.obj2) // prints "Object2"

I tried like this but it takes the whole enum as param. But my case is different from it. Any help would be appreciated.

Thanks

Upvotes: 0

Views: 1369

Answers (2)

Sweeper
Sweeper

Reputation: 271040

The linked question is actually quite close - you just have to change the parameter type to just T, instead of T.Type:

func printCase<T : RawRepresentable>(_ e: T) where T.RawValue == String {
    print(e.rawValue)
}

Since you are accepting an instance of the enum, not the enum type itself.

Of course, you don't have to restrict this to enums where T.RawValue == String, since print can print Anything.

Upvotes: 2

David Pasztor
David Pasztor

Reputation: 54706

You just need to define a generic function that takes a RawRepresentable and returns its rawValue property.

func rawValue<T: RawRepresentable>(of case: T) -> T.RawValue {
    `case`.rawValue
}

rawValue(of: Foo.obj2) // "Object2"
rawValue(of: Bar.obj1) // "Object1"

Upvotes: 1

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