Reputation: 49
Let's say I'm moving from the top of the peak with a giving distance of 1 nm before the peak (at left). How can I get the index or the coordinate of the arrival point?
data looks like this:
timeInS= [0.000000e+00, 1.000000e-10, 2.000000e-10, 3.000000e-10, 4.000000e-...]
force=[-0.0030, 20.3471, 41.1066, 8.4028, 60.1618 ...]
#distance is eucleadian distance
for i in range(len(force)-1):
distance.append ( math.sqrt( ((ts[i]-f[i])**2)+((ts[i+1]-f[i+1])**2) ))
please see plot here: force vs time
Upvotes: 0
Views: 218
Reputation: 702
let us suppose, we have point A= (t1, f1) at top and point C= (t2,f2), whose coordinates you know as shown in picture. Calculate the equation of the line
y = mx+c
Solve for fx and tx.
Upvotes: 1