CODEWITHSUNDEEP
javaregexstring
nickel
nickel

Reputation: 55

removes leading zeroes, but leaves one necessary From String in Java

Given:

a = 00099999325
b = 1254

How do I remove leading zeros but leaves one necessary

This is the output I'm expecting:

099999325
1254

Currently, am using this function but i need to optimize it :

//removes leading zeroes, but leaves one if necessary
public static String removeLeadingZeroes(String s) {

    return s.replaceFirst("^0+(?!$)", "");

}

can anyone help me please ? thank you for advanced

Upvotes: 0

Views: 65

Answers (1)

Youcef LAIDANI
Youcef LAIDANI

Reputation: 59950

You can use this regex ^0*(0\d+) like this:

return s.replaceFirst("^0*(0\\d+)", "$1");

I/O

000099999325 -> 099999325
1254         -> 1254
1230004      -> 1230004

Upvotes: 1

Related Questions