Reputation: 3805
I have parameters for 4 variables as shown below
parameters <- data.frame(param.x1 = 0.02,
param.x2 = 0.03,
param.x1.sq = 0.05,
param.x2.sq = 0.03)
I also have corresponding values of the 4 variables shown below
set.seed(123)
dat <- data.frame(
x1 = rnorm(5),
x2 = rnorm(5),
x1.sq = rnorm(5),
x2.sq = rnorm(5))
I want to multiply each variable by its corresponding parameter and then add the product as shown below
final.val <- (dat$x1 * parameters$param.x1) +
(dat$x2 * parameters$param.x2) +
(dat$x1.sq * parameters$param.x1.sq) +
(dat$x2.sq * parameters$param.x2.sq)
How can I do this without typing the entire equation in case I have more than 4 variables? The order of my variables and parameters will always be same.
Upvotes: 0
Views: 32
Reputation: 395
In practice you want to perform a matrix operation, therefore I would do the following:
c(as.matrix(dat)%*%t(as.matrix(parameters)))
Upvotes: 1
Reputation: 39613
You can try:
mapply(function(x,y) x*y,dat,parameters)
x1 x2 x1.sq x2.sq
[1,] -0.011209513 0.05145195 0.061204090 0.05360739
[2,] -0.004603550 0.01382749 0.017990691 0.01493551
[3,] 0.031174166 -0.03795184 0.020038573 -0.05899851
[4,] 0.001410168 -0.02060559 0.005534136 0.02104068
[5,] 0.002585755 -0.01336986 -0.027792057 -0.01418374
Upvotes: 1
Reputation: 887691
We can use Map/Reduce
final.val2 <- Reduce(`+`, Map(`*`, dat, parameters))
Or use %*%
final.val3 <- (as.matrix(dat) %*% unlist(parameters))[,1]
-checking with OP's output
identical(final.val, final.val2)
#[1] TRUE
identical(final.val, final.val3)
#[1] TRUE
Or another option with sweep/rowSums
rowSums(sweep(dat, 2, unlist(parameters), `*`))
Upvotes: 1