CODEWITHSUNDEEP
pythonpython-3.xpandaslistdataframe
arv
arv

Reputation: 398

Python recognise with and without quotation marks

I have this line of code that works.

price = df1.loc[:, ['price', 'date']]

I need to emulate this is as a loop with other metrics like sales and revenue. Is this possible? i.e How do I get Python to reference a word in the list both with and without quotation marks?

listx = [price,sales, revenue]
for a in listx:
    a = df1.loc[:, ['a', 'date']]

Upvotes: 0

Views: 87

Answers (2)

MrNobody33
MrNobody33

Reputation: 6483

IIUC, you could do something like this, using a list comprehension:

listx = ['price','sales', 'revenue']
price, sales, revenue=[df1.loc[:, [a, 'date']] for a in listx]

For a general way, this could be an approach using globals:

listx = ['price','sales', 'revenue']
for a in listx:
    globals().update({a:df1.loc[:, [a, 'date']]})

As is requested in the comments, please provide a minimal reproducible example in the future.

Upvotes: 2

above_c_level
above_c_level

Reputation: 3929

One way to do it is to save it in a dict:

metrics = {}
listx = ['price', 'sales', 'revenue']
for a in listx:
    metrics[a] = df1.loc[:, [a, 'date']]

Now you can access the metrics with metric['sales'] etc.

Maybe I misunderstood your question. Please provide a minimal reproducible example in the future.

Upvotes: 2

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