CODEWITHSUNDEEP
c++
vrbilgi
vrbilgi

Reputation: 5803

Error C2064: term does not evaluate to a function taking 1 argument

When I try the below program its gives me the :error C2064: I tried in google but not able to find the exact reason. Please help.

class myClass 
{
    public:
        void function(myClass dTemp)
        {
            cout<<"Inside myClass: taking myClass parameter"<<endl;
        }
};

. 

int main()
{

    myClass myClassTemp;
    myClass myClassTemp1;

    myClassTemp(myClassTemp1);// error C2064: term does not evaluate to a function taking 1 argument.

return 0;
};

Upvotes: 0

Views: 5368

Answers (3)

Cem Kalyoncu
Cem Kalyoncu

Reputation: 14603

You should include your function name when calling.

myClassTemp.function(myClassTemp1)

Or if your intention is functor object do it following way:

class myClass 
{
    public:
        void operator() (myClass dTemp)
        {
            cout<<"Inside myClass: taking myClass parameter"<<endl;
        }
};

. 
int main()
{

    myClass myClassTemp;
    myClass myClassTemp1;

    myClassTemp(myClassTemp1);

return 0;
};

Upvotes: 5

Xeo
Xeo

Reputation: 131829

Did you mean to be able to call an object of type myClass like a function? You need to overload operator() for that:

void operator()(myClass dTemp){
  // ...
}

If you instead wanted to call the function, well, you should actually do so:

myClassTemp.function(myClassTemp1);

Upvotes: 6

Kiril Kirov
Kiril Kirov

Reputation: 38173

This should be

//          vvvvvvvv
myClassTemp.function(myClassTemp1);

Upvotes: 3

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