CODEWITHSUNDEEP
pine-script
fjgwey
fjgwey

Reputation: 27

How to make an or condition with two constant color values?

kcolor = iff( sqzval > 0,
     iff( sqzval > nz(sqzval[1]), color.lime, color.green),
     iff( sqzval < nz(sqzval[1]), color.red, color.maroon))

This is the relevant code. I have a variable with multiple conditions, so it will be and (variable name) something something. I want a condition that checks if kcolor is either color.lime or color.maroon, and likewise for color.green or color.red.

I've tried a couple ways but I haven't found anything that works. kcolor = color.lime or color.maroon doesn't work, it gives me a syntax error at input 'kcolor'. When I change the = to a ==, it doesn't work because Cannot call 'operator or' with arguments (series[bool], literal color).

I know that I most likely have to make a condition that outputs a boolean value, but I don't know exactly how to do that.

Any help appreciated, thanks in advance.

Upvotes: 0

Views: 56

Answers (2)

fjgwey
fjgwey

Reputation: 27

This is the workaround I used. The above answer is valid too, this is what I came up with.

sqzmombull = iff( sqzval > 0,
     iff( sqzval > nz(sqzval[1]), true, na),
     iff( sqzval < nz(sqzval[1]), na, true))
     
sqzmombear = iff( sqzval > 0,
     iff( sqzval > nz(sqzval[1]), na, true),
     iff( sqzval < nz(sqzval[1]), true, na))

Upvotes: 0

PineCoders-LucF
PineCoders-LucF

Reputation: 8779

limeOrMaroon = kcolor == color.lime or kcolor == color.maroon
greenOrRed = kcolor == color.green or kcolor == color.red

Upvotes: 1

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