CODEWITHSUNDEEP
javascript
Raul Delgado de Luna
Raul Delgado de Luna

Reputation: 81

build a regex password 6 letters, 2 digits, and 1 punctuation

I am trying to build a regex that matches for the following

  1. 6 letters
  2. digits
  3. 1 punctuation

my special characters from my backend to support js special_characters = "[~\!@#\$%\^&\*\(\)_\+{}\":;,'\[\]]"

and a minimum of a length of at least 8 or longer.

my password javascript client-side is the following, but however, how can I build a regex with the following data?

if (password === '') {
    addErrorTo('password', data['message']['password1']);
} else if(password){
    addErrorTo('password', data['message']['password1']);
}else {
    removeErrorFrom('password');
}

Upvotes: 1

Views: 200

Answers (3)

Jack Cole
Jack Cole

Reputation: 1804

You can use multiple REGEXes to check for each requirement.

let containsAtLeastSixChars = /(\w[^\w]*){6}/.test(password);
let containsAtLeastTwoDigits = /(\d[^\d]*){2}/.test(password);
let containsAtLeastOnePunct = new RegExp(special_characters).test(password);
let isAtLeast8Digits = password.length >= 8;

Then if any of these booleans are false, you can inform the user. A well designed site will show which one is wrong, and display what the user needs to fix.

Upvotes: 2

sagiri
sagiri

Reputation: 1

^(?=.*[0-9]).{2}(?=.*[a-zA-Z]).{6}(?=.*[!@#$%^&*(),.?":{}|<>]).{1}$

6Letters, 2digits, and 1 special character.

Upvotes: 0

George
George

Reputation: 591

First check if password.length >= 6

Then I would do it like this:

  1. Set up a letterCount, numCount, puncCount
  2. Loop through the string and earch time you encounter a letter, increase the letterCount (letterCount++), each time you encounter a number increase numCount and so on.
  3. Then validate your password using the counter variables.

This is a good approach because you can tell the user what went wrong. For example, if they only entered 1 number, you can see that from the numCount and tell them specifically that they need at least 2 numbers. You can't do that with just one Regex.

EDIT: Heres the code:

for (let i = 0; i < password.length; i++) {
  const currentChar = password[i];
  if (checkIfLetter(currentChar)) {
    letterCount++;
  }

  if (checkIfNumber(currentChar)) {
    numCount++;
  }
  
  if (checkIfPunc(currentChar)) {
    puncCount++;
  }
}

Then check if the numCount > 2 and so on. I would write the actual regexs but I don't know them myself. It should be pretty easy, just return true if the provided char is a letter for the first function, a number for the second one and so on.

Upvotes: 2

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