CODEWITHSUNDEEP
pythonarrayslistinitialization
Jacob Hornbeck
Jacob Hornbeck

Reputation: 518

Simple way to create an incrementing Python array

I am wanting to initialize an array (in Python) that goes from 1 to some number n. I am wondering how I would do that in the simplest way...

In this answer, they share a way to initialize an array with all the same value, but I want to initialize mine to be more like this: [1,2,3,4,5,6,7,8,9,10] if n = 10

I know I could do something like:

n = int(input("Enter a number: "))

arr = 0 * n

for (i in range(len(arr))):
    arr[i] = i+1

But I want it simpler... I'm sort of new to Python, so I don't know a whole lot. Would someone be able to show me how (and explain it or give a reference) to initialize an "incrementing array"?

Thank you!

Upvotes: 1

Views: 4370

Answers (2)

apridos
apridos

Reputation: 182

Update Based on Karl's answer, you should have something like this :

arr = list(range(1, n+1))
print(arr)

======================================================= I'm not really sure about your question. but let me try

n = int(input("Enter a number: "))
arr = []
for i in range (1,n+1):
    arr.append(i)
print(arr)

use append to add any item to the tail of the array.

Upvotes: 1

Karl Knechtel
Karl Knechtel

Reputation: 61498

But I want it simpler

Make sure you understand how range works and what it actually does. Since it is already a sequence, and since it already contains the exact values you want, all you need to do in order to get a list is to convert the type, by creating a list from the range.

It looks like:

list(range(n))

Yep, that's it.

Upvotes: 4

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