CODEWITHSUNDEEP
c++arrayslinuxfunctionloops
charmingsalamander
charmingsalamander

Reputation: 17

allocation on the heap of 3d arrays in c++

I'm trying to use nested for-loops and new, to write the C++ code that creates a 3x6x4 3D int array (with the name C) in the heap.

Heres my code so far:

#include <iostream>  
using namespace std;  
//#include "we.hh"

#define X 3
#define Y 6
#define Z 4

int main() {  

  //***<your_code_here>***
  int *** C;
  C = new int**[X * Y * Z];
  int i, j, k;

  for (int i = 0; i < X; i++)
    C[i] = new int*[X]; 

  for (int j = 0; j < Y; j++)
    C[i][j] = new int[Y];

  for (int k = 0; k < Z; k++) 
    C[i][j][k] = new int[Z];

I get an error on the last line saying invalid conversion from int* to int. Any help would be appreciated.

Upvotes: 0

Views: 148

Answers (2)

john
john

Reputation: 88027

You need to nest your loops not sequence them, you also have one too many loops, and you've allocated the wrong number of pointers at each level. Like this

int *** C = new int**[X];
for (int i = 0; i < X; i++)
{
    C[i] = new int*[Y]; 
    for (int j = 0; j < Y; j++)
    {
        C[i][j] = new int[Z];
    }
}

Upvotes: 0

Chris Dodd
Chris Dodd

Reputation: 126468

You're using C++ so don't use raw arrays or new.

std::array<std::array<std::array, Z>, Y>, X>   C;

done.

Upvotes: 1

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