CODEWITHSUNDEEP
javascriptregex
Sharki
Sharki

Reputation: 424

Regex, match values inside of curly brackets

Having the next string

{ Hello, testing, hi stack overflow, how is it going }

Match every word inside of curly brackets without the comma.

I tried this:

\{(.*)\} which take all, commas and brackets included.

\{\w+\} I thought this will work for words but it wont, why?

Updated

Tried this but I got null, why?

    str = "{ Hello, testing, hi stack overflow, how is it going }";
    str2 = str.match("\{(.*?)\}")[1]; // Taking the second group
    console.log(str2);
    console.log(str2.match("/w+"));

Upvotes: 0

Views: 126

Answers (2)

Luke in IT
Luke in IT

Reputation: 59

Perhaps slightly complex, but this one line makes a string into an array of the words in the string.

str = str.replace(/^\{([^}]*)\}$, "$1"/).split(/[\W]/).filter(x => x);
// ^       -- string start
// \{      -- find {
// ([^}]*) -- match zero or more characters not between [^ and ]
// \}      -- find }
// $       -- string end
// split(/[\W]/) removes anything not 0-9 a-z A-Z and underscore
// filter(x => x) removes empty strings from the array

To get the result as a string, use this instead.

str.replace(/[{},]+/g, "").replace(/(^\s+)|(\s$)/g, "")
// /[{},]+/g       -- remove all instances of "{", "}", and ","
// /(^\s+)|(\s$)/g -- remove leading and trailing whitespace

Upvotes: 0

ha-neul
ha-neul

Reputation: 3248

did you try:

first get everything between {} by using

\{(.*?)\}

then get all words inside of the resulting string.

\w+

Here is an explanation:

\w+ matches any word character (equal to [a-zA-Z0-9_])
+ Quantifier — Matches between one and unlimited times, as many times as possible, giving back as needed

Upvotes: 1

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