CODEWITHSUNDEEP
java
Dakar 2021
Dakar 2021

Reputation: 3

How to extract string from response?

I already searched in Google about this matter. I just want to extract these strings 192.168.90.20, 80, 5225 and 96656 from this response.

The response is:

Ready 192.168.90.20:80 1.1
YID 5225 PID 96656
Connected

I used this code, but it didn't work.

public static final Pattern myPat1 = Pattern.compile("Ready (.+):(.+))",Pattern.CASE_INSENSITIVE);
public static final Pattern myPat2 = Pattern.compile("YID (.+) PID (.+))",Pattern.CASE_INSENSITIVE);

Matcher matcher1 = myPat1.matcher(response);
Matcher matcher2 = myPat2.matcher(response);

if (matcher1.matches()) {
    System.out.println(matcher1.group(1));
    System.out.println(Integer.parseInt(matcher.group(2));
} else {
    System.out.println("Error");
}

if (matcher2.matches()) {
    System.out.println(matcher2.group(1));
    System.out.println(matcher2.group(2));
} else {
    System.out.println("Error");
}

Upvotes: 0

Views: 71

Answers (1)

Abra
Abra

Reputation: 20914

The following works for me.

String response = """
        Ready 192.168.90.20:80 1.1
        YID 5225 PID 96656
        Connected""";
System.out.println(response);
Pattern pattern = Pattern.compile("([\\d.:]+)", Pattern.DOTALL);
Matcher matcher = pattern.matcher(response);
while (matcher.find()) {
    System.out.println(matcher.group(1));
}

The output is:

Ready 192.168.90.20:80 1.1
YID 5225 PID 96656
Connected
192.168.90.20:80
1.1
5225
96656

The code uses java text blocks.

Note that method matches tries to match the entire string, whereas method find searches for the next occurrence of the pattern in the string. Each time you call find, it starts searching from the end of the previous match.

Upvotes: 1

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