CODEWITHSUNDEEP
javascriptstringsubstring
Neo
Neo

Reputation: 119

Substring set of string between given characters in Javascript

String I get is

["2021-01-13T09:45:48.046Z","2021-01-14T09:45:48.096Z","2021-01-15T09:45:48.099Z"]

Here I want to delete substring from T to Z for converting to this form:

["2021-01-13","2021-01-14","2021-01-15"]

I did like that but it replaces only the first string and deletes others, How can I do this separately for each

notFound=notFound.replace(/\T.*\Z/g, '');

Can I do this with the javascript substring function?

Upvotes: 4

Views: 245

Answers (5)

The fourth bird
The fourth bird

Reputation: 163342

If the strings are always in the same format, you could turn the string into an array and then also split on T and take the first part.

const str = '["2021-01-13T09:45:48.046Z","2021-01-14T09:45:48.096Z","2021-01-15T09:45:48.099Z"]';
let result = JSON.parse(str).map(s => s.split("T")[0]);
console.log(result);

For a specific match, you could use a pattern to match the datetime like format ^(\d{4}-\d{2}-\d{2}T)\d{2}:\d{2}:\d{2}\.\d{3}Z$ and replace with capturing group 1.

const str = '["2021-01-13T09:45:48.046Z","2021-01-14T09:45:48.096Z","2021-01-15T09:45:48.099Z"]';
let result = JSON.parse(str).map(s =>
  s.replace(/^(\d{4}-\d{2}-\d{2})T\d{2}:\d{2}:\d{2}\.\d{3}Z$/, "$1")
);
console.log(result);

Upvotes: 1

Nina Scholz
Nina Scholz

Reputation: 386578

You could replace with an nongready search.

const
    data = '["2021-01-13T09:45:48.046Z","2021-01-14T09:45:48.096Z","2021-01-15T09:45:48.099Z"]',
    result = data.replace(/T.*?Z/g, '');

console.log(result);

Upvotes: 4

Petyor
Petyor

Reputation: 404

You've got it right, just do a loop like this:

["2021-01-13T09:45:48.046Z","2021-01-14T09:45:48.096Z","2021-01-15T09:45:48.099Z"].map(s => s.replace(/\T.*\Z/g, ''));

Upvotes: 2

costaparas
costaparas

Reputation: 5237

I think you mean you have an array initially, rather than a string, in which case, this answer should suffice.

You can use Array.prototype.map() to do the replacement on each element of the array.

const x = ["2021-01-13T09:45:48.046Z", "2021-01-14T09:45:48.096Z", "2021-01-15T09:45:48.099Z"];
const y = x.map(e => {
  return e.replace(/T.*Z/, "");
});
console.log(y);

Side note: you don't need to escape the T and Z in the regular expression, and the global flag is redundant.

Upvotes: 1

sourav satyam
sourav satyam

Reputation: 986

Because you said String so you will have to parse it.

const str = '["2021-01-13T09:45:48.046Z","2021-01-14T09:45:48.096Z","2021-01-15T09:45:48.099Z"]';

let x = JSON.parse(str).map((e) => e.replace(/\T.*\Z/g,  ''));

console.log(x);

Upvotes: 3

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