CODEWITHSUNDEEP
pythonpandasdataframedatetime
rshar
rshar

Reputation: 1477

Converting column type 'datetime64[ns]' to datetime in Python3

I would like to perform a comparison between the two dates (One from a pandas dataframe) in python3, another one is calculated. I would like to filter pandas dataframe if the values in the 'Publication_date' is equal to or less than the today's date and is greater than the date 10 years ago.

The pandas df looks like this:

       PMID  Publication_date
0  31611796  2019-09-27
1  33348808  2020-12-17  
2  12089324  2002-06-27
3  31028872  2019-04-25
4  26805781  2016-01-21

I am doing the comparison as shown below.

df[(df['Publication_date']> datetime.date.today() - datetime.timedelta(days=3650)) & 
                  (df['Publication_date']<= datetime.date.today())]

Above date filter when applied on the df should not give Row:3 of the df.

'Publication_date' column has type 'string'. I converted it to date using below line in my script.

df_phenotype['publication_date']= pd.to_datetime(df_phenotype['publication_date'])

But it changes the column type to 'datetime64[ns]' that makes the comparison incompatible between 'datetime64[ns]' and datetime.

How can I perform this comparison?

Any help is highly appreciated.

Upvotes: 1

Views: 591

Answers (1)

jezrael
jezrael

Reputation: 862641

You can use only pandas for working with datetimes - Timestamp.floor is for remove times from datetimes (set times to 00:00:00):

df['Publication_date']= pd.to_datetime(df['Publication_date'])

today = pd.to_datetime('now').floor('d')
df1 = df[(df['Publication_date']> today - pd.Timedelta(days=3650)) & 
                  (df['Publication_date']<= today)]

Also you can use 10 years offset:

today = pd.to_datetime('now').floor('d')
df1 = df[(df['Publication_date']> today - pd.offsets.DateOffset(years=10)) & 
                  (df['Publication_date']<= today)]

print (df1)
       PMID Publication_date
0  31611796       2019-09-27
1  33348808       2020-12-17
3  31028872       2019-04-25
4  26805781       2016-01-21

Upvotes: 1

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