CODEWITHSUNDEEP
javainputstreamoutputstreamzipoutputstreamzipinputstream
AlMahiyan
AlMahiyan

Reputation: 11

Java.util.zip.ZipException: invalid entry size (expected 18401 but got 0 bytes) when using putNextEntry() in ZipOutputStream?

I converted a zip file of 5 files into a byte array. I want to output a zip file on my disk from that bytearray. My process was first reading the byte[] into a ByteArrayInputStream then into a ZipInputStream.

InputStream plainTextStream = new ByteArrayInputStream(plainText);
ZipInputStream zipInStream = new ZipInputStream(plainTextStream);

I want this to be outputted into a zip file on my disk so here I thought I will need a file and a ZipOutPutStream passing that zip file.

ZipOutputStream zipOutStream = new ZipOutputStream(new FileOutputStream(file));

With a zip entry I traversed the ZipInPutStream writing to a FileOutputStream each entry, using a buffer. At the end of each main loop I put an entry into the ZipOutPutStream.

    ZipEntry entry = null;
    while((entry = zipInStream.getNextEntry()) != null){
        FileOutputStream fileOutStream = new FileOutputStream(entry.getName());
        byte[] byteBuff = new byte[1024];
        int bytesRead = 0;
        while ((bytesRead = zipInStream.read(byteBuff)) != -1)
        {
            fileOutStream.write(byteBuff, 0, bytesRead);
        }
        fileOutStream.close();
        zipOutStream.putNextEntry(entry);
        zipInStream.closeEntry();
    }

I add the first file from the zip (there are 5 files), but when trying to add the 2nd file, I get an error on

zipOutStream.putNextEntry(entry)

java.util.zip.ZipException: invalid entry size (expected 18401 but got 0 bytes)

Through debugging I can't figure out where it goes wrong. I assume it may have something to do with the buffer when putting in the first outputstream(entry.getName())? The bytesRead while loop could be an issue. This is all assuming the logic makes sense. I hope I can approach a solution to this error.

Upvotes: 1

Views: 9539

Answers (2)

Ashish Gupta
Ashish Gupta

Reputation: 311

To resolve (expected 18401 but got 0 bytes)

Create a new blank excel file.

Copy data from the file you copied from zip to the new created file in step 1.

Use the new file, it should work as its worked for me.

Thanks.

Upvotes: -3

Andreas
Andreas

Reputation: 159215

You never write the content of the zipped files to the zip output stream.

You don't need to write the output to a file stream, just write it directly to the zip output stream.

You should be using try-with-resources.

try (ZipInputStream zipInStream = new ZipInputStream(new ByteArrayInputStream(plainText));
     ZipOutputStream zipOutStream = new ZipOutputStream(new FileOutputStream(file));
) {
    byte[] byteBuff = new byte[1024];
    for (ZipEntry entry; (entry = zipInStream.getNextEntry()) != null; ) {
        zipOutStream.putNextEntry(entry);
        for (int bytesRead; (bytesRead = zipInStream.read(byteBuff)) != -1; ) {
            zipOutStream.write(byteBuff, 0, bytesRead);
        }
    }
}

There is no need to call closeEntry().

Upvotes: 1

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