CODEWITHSUNDEEP
javastringmethodscontainsstartswith
Enis
Enis

Reputation: 109

Method to check if the string contains certain elements that accepts a parameter String

I am a student and kind of new to Java. For my homework I have to:

The word must:

  1. Start with an uppercase letter
  2. End with a number
  3. Contain the word "cse".

I am asked to create a method inside some code homework that does a specific task, the method should check all the required conditions, the name of the method should be countTest and it accepts the String as a parameter.

I will show you my code but I don't know how to create this specific method.

Output format

System.out.println("There as a total number of words " + count + " and 
the ones that fulfill the condition are: " + condition);

The problem is, I dont know how to create the method or constructor or whatever it is called that calls all of the 3 methods inside it, and then connect that particular method to the main method! I hope you guys can understand I am new to this, thank you in advance!

enter image description here

public class D6_6 {
    public static void main(String[]args){
        Scanner sc = new Scanner(System.in);
        System.out.println("Type a number that is at least 7");
        int number = sc.nextInt();
        int count = 0;
        int condition = 0;
        do{
            if(number<7){
                System.out.println("You should type a number that is at least 7 or higher");
                number = sc.nextInt();
            }

        }
        while(number<7);
        sc.nextLine();
        String str;
        for(int i =0; i<number; i++){
            System.out.println("Type a word");
            str = sc.nextLine();
            count++;
        }
    }
    public boolean countTest(String str)    {

}```

Upvotes: 1

Views: 1083

Answers (2)

Enis
Enis

Reputation: 109

I think I did it, thank you guys very much, I appreciate it!

public class D6_6 {
    public static void main(String[] args) {
        Scanner sc = new Scanner(System.in);
        System.out.println("Type a number that is at least 7");
        int number = sc.nextInt();
        int count = 0;
        int condition = 0;
        do {
            if (number < 7) {
                System.out.println("You should type a number that is at least 7 or higher");
                number = sc.nextInt();
            }

        }
        while (number < 7);
        sc.nextLine();
        String str;
        for (int i = 0; i < number; i++) {
            System.out.println("Type a word");
            str = sc.nextLine();
            count++;
            if((countTest(str))){
                condition++;

            }
        }
        if(count == 0){
            System.out.println("No words typed");
        } else {
            System.out.println("Total number of words typed: " + count + ", which fulfill the condition: "+ condition);
        }
    }

    public static boolean countTest(String str) {
        return Character.isUpperCase(str.charAt(0)) && str.charAt(str.length() - 1) >= 48 || str.charAt(str.length() - 1) <= 57 || str.contains("cse");
    }

}```

Upvotes: 0

Sven
Sven

Reputation: 46

  1. To check if the word start with an uppercase: You can do that by first selecting the character you want to check by str.charAt(0). This will return a char that is the first letter of the input str.
    To check if this char is an uppercase letter, you can easily use char.isUppercase(). This will return a boolean. You have to replace char by the name of the variable were you put the char of str.charAt(0) in.

  2. To check if the last character is a number: You can do that again by first selecting the last character by str.charAt(str.length()-1), were string.length-1 is the number of the last character.
    To check if this character is a number, you can use the ascii table. Every character has it's own number. So if you want to check if your character is between 0 and 9, you can use char >= 48 || char <= 57 (look up in the ascii table). Again, char is the name of the variable were you put the char of str.charAt(str.length()-1) in.

  3. To check if the word contains "cse": There is a very easy method for that: str.contains("cse") will return a boolean that is true when "cse" is in the word and false when the word does not contain "cse".

I hope it is clear for you now!

Upvotes: 2

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