CODEWITHSUNDEEP
pythondjango
Viktor
Viktor

Reputation: 489

__init__() got an unexpected keyword argument 'request'

A silly question: why do we get TypeError on the super's __init__ only? Aren't they supposed to take the same arguments?

class MyModelForm(forms.ModelForm):
    class Meta:
        model = MyModel

    def __init__(self, *args, **kwargs):
        # self.request = kwargs.pop('request')
        super().__init__(*args, **kwargs)

If it's the same method of the same forms.ModelForm class, why does the first one accept request and the second doesn't?

Here's ModelForm's __init__:

def __init__(self, data=None, files=None, auto_id='id_%s', prefix=None,
                 initial=None, error_class=ErrorList, label_suffix=None,
                 empty_permitted=False, instance=None, use_required_attribute=None,
                 renderer=None):

So when I'm calling form = MyModelForm(request=request) why does the MyModelForm's __init__ let it through?

Upvotes: 3

Views: 7289

Answers (1)

ThePyGuy
ThePyGuy

Reputation: 18456

why do we get TypeError on the super's init only? Aren't they supposed to take the same arguments?

No, they are not.

When you are creating your ModelForm class, its constructor's signature is def __init__(self, *args, **kwargs), so there is not any keywords, just **kwargs that allows any number of keyword arguments to be passed while creating the instance of the MyModelForm class.

The second function signature is coming from the django ModelForm class, which has limited number of keyword arguments, and only those keyword arguments are accepted. You can try passing some random kwargs, like foo='bar', it will again throw error.

def __init__(self, data=None, files=None, auto_id='id_%s', prefix=None,
                 initial=None, error_class=ErrorList, label_suffix=None,
                 empty_permitted=False, instance=None, use_required_attribute=None,
                 renderer=None):

But if it also had **kwargs in the end, then it'd also accept any keyword arguments.

Upvotes: 5

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