Reputation: 211
A data wrangling question:
I have a dataframe of hourly animal tracking points with columns for id, time, and whether the animal is on land or in water (0 = water; 1 = land). It looks something like this:
set.seed(13)
n <- 100
dat <- data.frame(id = rep(1:5, each = 10),
datetime=seq(as.POSIXct("2020-12-26 00:00:00"), as.POSIXct("2020-12-30 3:00:00"), by = "hour"),
land = sample(0:1, n, replace = TRUE))
What I need to do is flag the first row after which the animal uses land at least once for 3 straight days. I tried doing something like this:
dat$ymd <- ymd(dat$datetime[1]) # make column for year-month-day
# add land points within each id group
land.pts <- dat %>%
group_by(id, ymd) %>%
arrange(id, datetime) %>%
drop_na(land) %>%
mutate(all.land = cumsum(land))
#flag days that have any land points
flag <- land.pts %>%
group_by(id, ymd) %>%
arrange(id, datetime) %>%
slice(n()) %>%
mutate(flag = if_else(all.land == 0,0,1))
# Combine flagged dataframe with full dataframe
comb <- left_join(land.pts, flag)
comb[is.na(comb)] <- 1
and then I tried this:
x = comb %>%
group_by(id) %>%
arrange(id, datetime) %>%
mutate(time.land=ifelse(land==0 | is.na(lag(land)) | lag(land)==0 | flag==0,
0,
difftime(datetime, lag(datetime), units="days")))
But I still can't quite wrap my head around what to do to make it so that I can figure out when the animal has been on land at least once for three days straight, and then flag that first point on land. Thanks so much for any help you can provide!
Upvotes: 0
Views: 358
Reputation: 388982
Create a date column from the timestamp. Summarise the data and keep only 1 row for each id
and date
which shows whether the animal
was on land even once in the entire day.
Use zoo
's rollapply
function to mark the first day as TRUE
if the next 3 days the animal was on land.
library(dplyr)
library(zoo)
dat <- dat %>% mutate(date = as.Date(datetime))
dat %>%
group_by(id, date) %>%
summarise(on_land = any(land == 1)) %>%
mutate(consec_three = rollapply(on_land, 3,all, align = 'left', fill = NA)) %>%
ungroup %>%
#If you want all the rows of the data
left_join(dat, by = c('id', 'date'))
Upvotes: 2