CODEWITHSUNDEEP
c++oopoverloading
MinaSabrawy
MinaSabrawy

Reputation: 43

How can I invoke an overloaded () operator on the keyword this?

The following works but feels ugly when I do the (*this)(5) part.

struct MyStruct
{
    void operator()(int a)
    {
        // Do something with "a"
    }

    void myFunc()
    {
        (*this)(5);
    }
};

I will need to overload the () operator and use it from within other class methods.

Upvotes: 2

Views: 333

Answers (1)

bolov
bolov

Reputation: 75894

You have a few options:

  • (*this)(5)

  • this->operator()(5)

  • or just operator()(5)

  • Create a method that you call from within the operator(), e.g.:

    void do_work(int a) { /* ... */ }
void operator()(int a) { do_work(a); }
void myFunc() { do_work(5); }

Whichever you choose is just a matter of personal taste.

Just for fun, here are some more (ridiculous) options:

  • std::invoke (mentioned in comments):

    std::invoke(&MyStruct::operator(), this, 5);

  • mem_fn:

    auto call_op = std::mem_fn(&MyStruct::operator());
call_op(this, 5);

  • lambda:

    auto call_op = [this] (int a) { operator()(a); };
call_op(5);

  • bind_front

    auto call_op = std::bind_front(&MyStruct::operator(), this);
call_op(5);

Upvotes: 10

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