CODEWITHSUNDEEP
python
user17740496
user17740496

Reputation:

How to get count of consonants

I have to get count of consonants present in given string but seems like something missing. What do I need to modify to get the expected result?

My code :

var = 'aaeouAIyuiodffgXUEEE'
vowels='aeiou'
for i in vowels:
  if i is not var:
    print(var)

Expected result:

y 1
d 1
f 2
g 1
x 1

Upvotes: 0

Views: 1007

Answers (3)

Gowtham Jayachandiran
Gowtham Jayachandiran

Reputation: 118

If you want to achieve the same output without any module, we can use LIST to generate similar outcome.

    var = 'aaeouAIyuiodffgXUEEE'
    vowels='aeiou'
    
    l = []
    for i in var.lower():
        if i not in vowels:
            l.append(i)
    for i in sorted(set(l)):
        print(i, l.count(i))

output:

d 1
f 2
g 1
x 1
y 1

To know the total consonants, use "sum(l)"

Upvotes: 0

user7864386
user7864386

Reputation:

You can use collections.Counter for this job. It's a dict subclass where each element is stored as dictionary keys and their counts are stored as dictionary values. So you can access the counts like:

>>> counts['y']
1

Then use sorted function on tuples of key-value pairs to sort the letters by alphabetical order and use dict constructor to re-construct the dictionary.

from collections import Counter
var = 'aaeouAIyuiodffgXUEEE'
vowels='aeiou'
counts = Counter([x for x in var.lower() if x not in vowels])
counts = dict(sorted(counts.items()))

Output:

{'d': 1, 'f': 2, 'g': 1, 'x': 1, 'y': 1}

You can find the sum of all consonants by:

total = sum(counts.values())

Output:

6

Upvotes: 3

Mario Mateaș
Mario Mateaș

Reputation: 1216

You should use an iterator i to navigate through the whole string var, character by character, and check for each character if it is a constant (or not). Using a vowels string is very helpful, and you should check if at least one of the characters in it is equal to i. Python has already a function for that.

Something like that:

for i in var:
        if i not in vowels:
                # increase the consonant counter

How to increase the consonant counter? Well, you could use a dictionary that uses consonants as keys. For example:

cons = {'b': 0, 'c': 0, ...}

Don't forget to set all the values to 0 first. You could also create the dictionary using a for loop (if you want to do it faster and more efficient).

Now, whenever you find a consonant, just do cons[i] = cons[i]+1. In the end, iterate through the dictionary and output every key, together with their values.

Upvotes: 0

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