CODEWITHSUNDEEP
c++stringc++11g++
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MxtApps

Reputation: 21

Why doesn't g++ recognize stoi even using C++11?

I have this function in C++11:

bool ccc(const string cc) {
    
vector<string> digits;
    
int aux;
    
for(int n = 0; n < cc.length(); ++n) {
    
digits.push_back(to_string(cc[n])); }
    
for(int s = 1; s < digits.size(); s += 2) {
    
aux = stoi(digits[s]);
    
aux *= 2;
    
digits[s] = to_string(aux);
    
aux = 0;
    
for(int f = 0; f < digits[s].length(); ++f) {
    
aux += stoi(digits[s][f]); }
    
digits[s] = to_string(aux);
    
aux = 0; }
    
for(int b = 0; b < digits.size(); ++b) {
    
aux += stoi(digits[b]); }
    
aux *= 9;
    
aux %= 10;
    
return (aux == 0); }

And I get this error when compiling with g++ with the -std=c++11 flag:

crecarche.cpp: In function ‘bool ccc(std::string)’:
    
crecarche.cpp:18:12: error: no matching function for call to ‘stoi(__gnu_cxx::__alloc_traits<std::allocator<char>, char>::value_type&)’
    
18 | aux += stoi(digits[s][f]); }
        |        ~~~~^~~~~~~~~~~~~~

But I used the stoi function after and I did not get any error with that line.

Why is the compiler throwing me this error and how can I fix it?

Upvotes: 1

Views: 57

Answers (1)

Florian Weimer
Florian Weimer

Reputation: 33719

The error message is telling you that the argument you pass to stoi is of the type

__gnu_cxx::__alloc_traits<std::allocator<char>, char>::value_type&

which is a fancy way of saying char&. This happens because digits[s] is already of type string&, and subscribing it further gives you a char&.

It's not clear to me what you are trying to accomplish. Maybe you need to remove the extra subscript, or use digits[s][f] - '0' to compute the digit value. C++ requires that the decimal digits are represented by subsequent code points, so this works even in theoretical implementations which are not based on the ISO 646 subset of Unicode.

Upvotes: 1

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