Reputation: 10709
I am trying to iterate through a number .rtf files and for each file: read the file, perform some operations, and then write new files into a sub-directory as plain text files with the same name as the original file, but with .txt extensions. The problem I am having is with the file naming.
If a file is named foo.rtf, I want the new file in the subdirectory to be foo.txt. here is my code:
import glob
import os
import numpy as np
dir_path = '/Users/me/Desktop/test/'
file_suffix = '*.rtf'
output_dir = os.mkdir('sub_dir')
for item in glob.iglob(dir_path + file_suffix):
with open(item, "r") as infile:
reader = infile.readlines()
matrix = []
for row in reader:
row = str(row)
row = row.split()
row = [int(value) for value in row]
matrix.append(row)
np_matrix = np.array(matrix)
inv_matrix = np.transpose(np_matrix)
new_file_name = item.replace('*.rtf', '*.txt') # i think this line is the problem?
os.chdir(output_dir)
with open(new_file_name, mode="w") as outfile:
outfile.write(inv_matrix)
When I run this code, I get a Type Error:
TypeError: coercing to Unicode: need string or buffer, NoneType found
How can I fix my code to write new files into a subdirectory and change the file extensions from .rtf to .txt? Thanks for the help.
Upvotes: 0
Views: 342
Reputation: 16900
I've never used glob, but here's an alternative way without using a module:
You can easily strip the suffix using
name = name[:name.rfind('.')]
and then add the new suffix:
name = name + '.txt'
Why not using a function ?
def change_suffix(string, new_suffix):
i = string.rfind('.')
if i < 0:
raise ValueError, 'string does not have a suffix'
if not new_suffix[0] == '.':
new_suffix += '.'
return string[:i] + new_suffix
Upvotes: 2
Reputation: 21175
glob.iglob()
yields pathnames, without the character '*'.
therefore your line should be:
new_file_name = item.replace('.rtf', '.txt')
consider working with clearer names (reserve 'filename' for a file name and use 'path' for a complete path to a file; use 'path_original' instead of 'item'), os.extsep ('.' in Windows) and os.path.splitext():
path_txt = os.extsep.join([os.path.splitext(path_original)[0], 'txt'])
now the best hint of all: numpy can probably read your file directly:
data = np.genfromtxt(filename, unpack=True)
(see also here)
To better understand where your TypeError
comes from, wrap your code in the following try/except block:
try:
(your code)
except:
import traceback
traceback.print_exc()
Upvotes: 0
Reputation: 19623
Instead of item.replace
, check out some of the functions in the os.path
module (http://docs.python.org/library/os.path.html). They're made for splitting up and recombining parts of filenames. For instance, os.path.splitext
will split a filename into a file path and a file extension.
Let's say you have a file /tmp/foo.rtf
and you want to move it to /tmp/foo.txt
:
old_file = '/tmp/foo.rtf'
(file,ext) = os.path.splitext(old_file)
print 'File=%s Extension=%s' % (file,ext)
new_file = '%s%s' % (file,'.txt')
print 'New file = %s' % (new_file)
Or if you want the one line version:
old_file = '/tmp/foo.rtf'
new_file = '%s%s' % (os.path.splitext(old_file)[0],'.txt')
Upvotes: 3