CODEWITHSUNDEEP
javascript
Vladeezy
Vladeezy

Reputation: 187

How to make every single value of array suitable in IF statement?

For example i have an array with 100 values, let it be a[1,2,3...100]
Can I create a if check that will be suitable for any value from the array?
like:

if(value === a[any index]){
//do smth
}

almost sure that it can be done but don't know how, can you help me with that?

Upvotes: 0

Views: 42

Answers (4)

Jakub Kraus
Jakub Kraus

Reputation: 11

You should use the ES7 array.includes(). If it finds a given value in your array it will return a True boolean, else it will return False.

Example:

console.log([1,2,3].includes(2)) //True

console.log([1,2,3,4,5].includes(6)) //False

Upvotes: 1

Mushroomator
Mushroomator

Reputation: 9228

You can use an Object or Array to hold functions as values and then lookup a specific function depending on a given value to run different code based on that value.

function doSomething(){console.log("Something")}
function doSomethingElse(){console.log("Something else")}
function doAnotherThing(){console.log("Another thing")}

// specify value when to run a certain function and the function to run
const whatToDo = {
  "x": doSomething,
  "y": doSomethingElse,
  "z": doAnotherThing
}

// depending on some value the appropriate function will be run
const someValue = "z";
whatToDo[someValue]();

// or when using indices
const whatToDoArray = [doSomething, doSomethingElse, doAnotherThing];

// choose a function randomly
const randomValue = Math.floor(Math.random() * whatToDoArray.length);
whatToDoArray[randomValue]();

Upvotes: 0

Asplund
Asplund

Reputation: 2486

// for of
for (const item of a) {
  if (value === item) {

  }
}

// traditional for loop
for (let i = 0; i < a.length; i++) {
  if (value === array[i]) {

  }
}

// forEach
a.forEach(item => {
  if (value === array[i]) {

  }
});

Upvotes: 1

Ismael Padilla
Ismael Padilla

Reputation: 5566

You can use forEach:

a.forEach(element => {
  if (value === element) {
    // do something
  }
});

Upvotes: 1

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