CODEWITHSUNDEEP
python
jason
jason

Reputation: 31

How can I find if a value lies between two specific thresholds regardless of the order in which the thresholds are given?

For example, if I have a value a = 4 and two input thresholds t1 = 3 and t2 = 5.

a > t1 and a < t2 so the function func(a, t1, t2) returns true.

But if I input t1 = 5 and t2 = 3, even if a = 4 lies between the t1 and t2, the function returns false. How to solve this?

So far I write this function in this way, but it only works when t1 < t2. Is there some smart way to do this?

def func(a, t1, t2):
    if a > t1 and a < t2:
        return True
    else:
        return False

Upvotes: 0

Views: 807

Answers (2)

mkrieger1
mkrieger1

Reputation: 23250

You could order the two thresholds before using them in the comparison with a, for example by using the sorted function:

smaller, larger = sorted([t1, t2])

If t1 <= t2 then smaller will be t1 and larger will be t2, otherwise smaller will be t2 and larger will be t1.

def func(a, t1, t2):
    smaller, larger = sorted([t1, t2])
    return smaller < a < larger

Upvotes: 0

j1-lee
j1-lee

Reputation: 13939

You can use or:

def func(a, t1, t2):
    return t1 < a < t2 or t2 < a < t1

print(func(4, 3, 5)) # True
print(func(4, 5, 3)) # True
print(func(4, 1, 2)) # False

Note that python allows chained comparisons so that you don't need to write t1 < a and a < t2. Also, you don't need the redundant if statement as in:

if t1 < a < t2 or t2 < a < t1:
    return True
else:
    return False

Upvotes: 1

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