CODEWITHSUNDEEP
pythonlisttuples
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Reputation: 11

I'm trying to convert a tuple to a list in python

I'm trying to turn this:

('a','b',['a1','b1','b3',('a2',('ab','bd','cd'),'b2','c2')])

into this:

('a','b',['a1','b1','b3',('a2',['ab','bd','cd'],'b2','c2')])

changing the ('ab', 'bd', 'cd') to ['ab', 'bd', 'cd']

Upvotes: 1

Views: 97

Answers (1)

Aniketh Malyala
Aniketh Malyala

Reputation: 2670

You can use the list() function:

tup = ('ab', 'bd', 'cd')
lst = list(tup)
print(lst)

Output:

['ab', 'bd', 'cd']

EDIT:

If you want to get your output, it is a bit more complicated since tuples are immutable (unchangable), so we need to create a new tuple that stores the new change:

origTup = ('a','b',['a1','b1','b3',('a2',('ab','bd','cd'),'b2','c2')])
origLst = list(origTup) #convert origTup to a list so we can edit it

partialLst = list(origLst[2][3]) #extract ('a2',('ab','bd','cd'),'b2','c2') and change it to a list
partialLst[1] = list(partialLst[1]) #change ('ab','bd','cd') to a list
partialTup = tuple(partialLst) #convert ['a2',['ab','bd','cd'],'b2','c2'] back to a tuple

origLst[2][3] = partialTup #put the tuple back into our origLst

newTup = tuple(origLst) #create a new tuple that converts our origLst to a tuple

print(newTup)

Output:

('a', 'b', ['a1', 'b1', 'b3', ('a2', ['ab', 'bd', 'cd'], 'b2', 'c2')])

First, we convert origTup to a list, origLst so we can edit it. Then, we will extract ('a2',('ab','bd','cd'),'b2','c2') from our list and change it to a list: ['a2',('ab','bd','cd'),'b2','c2']

Now that we can edit it, we will change the first element, ('ab','bd','cd'), to a list: ['ab','bd','cd']. Then, we will again change the outer portion into a tuple as it originally was: ['a2',['ab','bd','cd'],'b2','c2'] into ('a2',['ab','bd','cd'],'b2','c2')

Finally, we set the element in our origLst to this tuple, and then create a new tuple to store our change.

I hope this helped! Please let me know if you need any further help or clarification!

Upvotes: 2

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