Reputation: 25
have a problem I can't solve directly using Snowflake docs:
I have a strings like 'abc\def'
need to split it to 'abc', 'def'
tried: split_to_table('abc\def', '\\') - error
strtok_to_array('abc\def', '\\') ==> [ "abcdef" ]
also, I've tried to replace it to better delimiter prior the split
replace('abc\cde','\\','_another_symbol_'); ==> abccde REGEXP_REPLACE('abc\cde','$$\$$','_another_symbol_') ==> abccde_another_symbol
but it doesn't work
any idea how to solve that?
Upvotes: 0
Views: 675
Reputation: 9788
If you just use SPLIT it will split the values into an array which you can then process however you want e.g.
with dataset as (
select $1 as col1 from
(values
('abc\\def'),
('ghi\\jkl'))
)
select col1, split(col1,'\\')
from dataset
COL1 | SPLIT(COL1,'\') |
---|---|
abc\def | [ "abc", "def" ] |
ghi\jkl | [ "ghi", "jkl" ] |
Upvotes: 2