CODEWITHSUNDEEP
phphtmltarget
Frontwichtel
Frontwichtel

Reputation: 1

HTML target in php with echo

I have a small problem, or I just can't find the solution. I have follow code in my site place.php

<?php $con = mysqli_connect("localhost", "root", "", "vmaxdbweb"); $res = mysqli_query($con, "SELECT * FROM tblplatz");

// Tabellenbeginn
echo "<table class='tbl'>";

    // Überschrift
    echo "<th>ID</th> <th>Bezeichung</th> <th>Code</th>";
    echo "<th>Notizen & Beurteilung</th> <th>Geodaten</th> <th>Details</th>";

    $lf = 1;
    while ($dsatz = mysqli_fetch_assoc($res))
    {
        // Speichere die Daten in der Sitzung mit dem Schlüssel 'pla_id'
        echo "<tr>";
        echo "<td>" . $dsatz["pla_id"] . "</td>";
        echo "<td>" . $dsatz["pla_bezeichnung"] . "</td>";
        echo "<td>" . $dsatz["pla_code"] . "</td>";
        echo "<td>" . $dsatz["pla_notiz_beurteilung"] . "</td>";
        echo "<td>" . $dsatz["pla_geodaten"] . "</td>";
        echo "<td><a href='content\placedetail.php?id=".$dsatz["pla_id"]."'>Details</a></td>";
        $lf = $lf + 1;
    }
    // Tabellenende
echo "</tabelle>";

mysqli_close($con);
?>

my laylout on the website looks like this

<!DOCTYPE html>
<html lang="en">
    <?php include __DIR__.'/header.inc.php' ?>

    <body>       
    <div class ="banner">   
        <h4>VmaxDB Web</h4>
        </div>
        <div class = "main">

            <div class = "menu">
                <header class="container">
                <?php include __DIR__.'/nav.inc.php' ?>
                </header>
            </div>          

            <div class = "stage">
                <div class = "stage-header">
                    <?=$title?>
                </div>
                                                  
                <div class = "content">
                    <main class="container">
                        <?php include __DIR__.'/../content/'.$currentPage.'.php' ?>
                    </main>
                </div>
            </div> 

        </div>   

        <div>
            <?php include __DIR__.'/footer.inc.php' ?>
        </div>

    </body>

</html>

and i would like open the link

echo "<td><a href='content\placedetail.php?id=".$dsatz["pla_id"]."'>Details</a></td>";

from site place.php

in the content/container place

Does anyone happen to have an idea? :) I've tried many things, unfortunately I can't find the solution, it always opens a new tab.

Upvotes: 0

Views: 88

Answers (1)

IMSoP
IMSoP

Reputation: 97948

Links in HTML are just a way to tell the browser to go to a new URL. They don't load content into a particular part of the page, or interact with the current page in any way.

So the simple answer is to make your link point to a complete page, which repeats the parts you want to be the same - such as your existing includes for header and footer. The PHP code can decide dynamically what to show based on query string parameters available in the $_GET array.

That said, there are two main ways you can load content into part of the page:

  • Using an <iframe> tag, which you could very roughly think of as embedding an extra browser tab inside the content. See for instance the MDN guide to the iframe element.
  • Using JavaScript running in the browser to fetch the new page from the server on the background, then insert it into the current page. For largely historical reasons this is called "AJAX", and you will find thousands of pages describing related techniques, and hundreds of libraries and frameworks built on top of those ideas. The modern building block for this is the fetch API.

Both techniques are a lot more fiddly to get right than just loading a full new page - particularly to avoid annoying users by breaking features like bookmarks and back/forward buttons.

Upvotes: 0

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