CODEWITHSUNDEEP
pythonnumpyfactorialpoisson
user2138149
user2138149

Reputation: 17170

Numpy power with array as exponent

I have a Python code containing the following lines:

# Poisson model

lambda_param = 3.0

x_model = numpy.linspace(0, 10, num=11, dtype=int)
y_model = numpy.zeros(10)

index = 0
for x in x_model:
    y_model[index] = numpy.power(lambda_param, x) / math.factorial(x) * numpy.exp(-lambda_param)
    index += 1

I want to write this in a more Pythonic way - without using a for loop.

I tried this:

y_model = numpy.power(lambda_param, x_model) / math.factorial(x_model) * numpy.exp(-lambda_param)

But this didn't seem to work, I would guess because math.factorial doesn't know how to operate on an array like object.

Is there a way to do this?

Upvotes: -1

Views: 89

Answers (2)

Onyambu
Onyambu

Reputation: 79288

This is the pmf for a poisson distribution. Use scipy.stats.poisson: Note that for poisson, x must be integers:

lambda_param = 3.0
x_model = np.arange(10)
y_model = np.zeros(10)

from scipy import stats
stats.poisson(lambda_param).pmf(x_model)
array([0.04978707, 0.14936121, 0.22404181, 0.22404181, 0.16803136,
       0.10081881, 0.05040941, 0.02160403, 0.00810151, 0.0027005 ])

Upvotes: 2

Brian61354270
Brian61354270

Reputation: 14434

You can use scipy.special.factorial as a factorial function that supports broadcasting over numpy arrays.

import numpy as np
import scipy.special

>>> scipy.special.factorial(np.arange(7))
array([  1.,   1.,   2.,   6.,  24., 120., 720.])

Upvotes: 1

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