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c#.netarrays
Tadeusz
Tadeusz

Reputation: 6873

How to convert a byte array to double array in C#?

I have a byte array which contains double values. I want to convert It to double array. Is it possible in C#?

Byte array looks like:

byte[] bytes; //I receive It from socket

double[] doubles;//I want to extract values to here

I created a byte-array in this way (C++):

double *d; //Array of doubles
byte * b = (byte *) d; //Array of bytes which i send over socket

Upvotes: 10

Views: 15430

Answers (2)

xanatos
xanatos

Reputation: 111810

I'll add a reference to the super-unsafe code from here C# unsafe value type array to byte array conversions

Be aware that it's based on an undocumented "feature" of C#, so tomorrow it could die.

[StructLayout(LayoutKind.Explicit)]
struct UnionArray
{
    [FieldOffset(0)]
    public byte[] Bytes;

    [FieldOffset(0)]
    public double[] Doubles;
}

static void Main(string[] args)
{
    // From bytes to floats - works
    byte[] bytes = { 0, 1, 2, 4, 8, 16, 32, 64 };
    UnionArray arry = new UnionArray { Bytes = bytes };

    for (int i = 0; i < arry.Bytes.Length / 8; i++)
        Console.WriteLine(arry.Doubles[i]);   
}

The only advantage of this method is that it doesn't really "copy" the array, so it's O(1) in space and time over other methods that copy the array that are O(n).

Upvotes: 9

Marc Gravell
Marc Gravell

Reputation: 1062492

You can't convert an array type; however:

byte[] bytes = ...
double[] values = new double[bytes.Length / 8];
for(int i = 0 ; i < values.Length ; i++)
    values[i] = BitConverter.ToDouble(bytes, i * 8);

or (alterntive):

byte[] bytes = ...
double[] values = new double[bytes.Length / 8];
Buffer.BlockCopy(bytes, 0, values, 0, values.Length * 8);

should do. You could also do it in unsafe code:

byte[] bytes = ...
double[] values = new double[bytes.Length / 8];
unsafe
{
    fixed(byte* tmp = bytes)
    fixed(double* dest = values)
    {
        double* source = (double*) tmp;
        for (int i = 0; i < values.Length; i++)
            dest[i] = source[i];
    }
}

not sure I recommend that, though

Upvotes: 17

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