Reputation: 1339
I have a table with a column named tags
. In this column, I have a comma-separated list like air conditioner, tv, fridge
.
I want to check if any of the words in the comma-separated column exists in a string like
Is there an air conditioner in the room?
So, the query should return a match as in the column tags
, the air conditioner
value exists.
I was thinking of using find_in_set
, but it will not work in this case as the logic should be reversed.
select * from products where find_in_set('Is there an air conditioner in the room?',tags) <> 0
UPDATE
I could use find_in_set
by separating the string into words and then checking against the tags column, but it will not work for a combination like "air conditioner" as it will spit like air, conditioner
.
MySQL version 5.7.44
Upvotes: 2
Views: 75
Reputation: 562348
SELECT * FROM products
CROSS JOIN JSON_TABLE(CONCAT('["', REGEXP_REPLACE(tags, ', *', '","'), '"]'),
'$[*]' COLUMNS(tag VARCHAR(20) PATH '$')
) AS j
WHERE LOCATE(j.tag, 'Is there an air conditioner in the room?');
Demo: https://dbfiddle.uk/ayNuWEqQ
This cannot be optimized with an index, just like any other substring-matching task.
The above solution with JSON_TABLE() requires MySQL 8.0 or later. MySQL 5.x is now past its end-of-life, but I understand some people have not upgraded. I'll leave this answer here for future folks who read this thread.
Upvotes: 1
Reputation: 781004
Don't use a comma-separated field in the first place. Normalize your schema by putting the tags into their own table with a foreign key pointing back to the products
table.
CREATE TABLE product_tags (
tag VARCHAR(100),
product_id INT,
PRIMARY KEY (tag, product_id),
FOREIGN KEY (product_id) REFERENCES products (id)
);
Then you can use
SELECT p.*
FROM products AS p
JOIN product_tags AS pt ON p.id = pt.product_id
WHERE LOCATE(pt.tag, 'Is there an air conditioner in the room?')
Upvotes: 2
Reputation: 15057
You can test it like this:
```
create table mytags (
id int(11),
tags varchar(64)
);
insert into mytags values(1,"air conditioner, tv, fridge");
SELECT * from mytags;
```
| id | tags |
|---:|:-----|
| 1 | air conditioner, tv, fridge |
```
SELECT * FROM mytags WHERE FIND_IN_SET("air conditioner",tags);
```
| id | tags |
|---:|:-----|
| 1 | air conditioner, tv, fridge |
Or remove always all spaces. Then you can find it with or without spaces Like:
```
SELECT * FROM mytags WHERE
FIND_IN_SET(REPLACE("airconditioner"," ",""),REPLACE(tags," ",""));
| id | tags |
|---:|:-----|
| 1 | air conditioner, tv, fridge |
Upvotes: 0