CODEWITHSUNDEEP
wpfmenuseparator
Sergey
Sergey

Reputation: 301

Custom menu Separator templated via Generic.xaml

I develop a DLL library that extends WPF Menu/MenuItem classes with some features including skinning. This library has the following classes:

public class MyMenu : Menu {...}
public class MyMenuItem : MenuItem {...}

Each class has a static constructor to override DefaultStyleKey so MyMenu and MyMenuItem use default styles defined in Generic.xaml:

<Style TargetType="{x:Type local:MyMenu}">...
<Style TargetType="{x:Type local:MyMenuItem}">...

Everything works fine. But I also need to realize a custom menu Separator which should be templated via Generic.xaml. So I have another class:

public class MySeparator : Separator {...}

I tried to use the approach described in MSDN: http://msdn.microsoft.com/en-us/library/system.windows.controls.menuitem.separatorstylekey(VS.85).aspx
This way (Generic.xaml):

<Style x:Key="{x:Static local:MyMenuItem.SeparatorStyleKey}" TargetType="{x:Type local:MySeparator}">
 <Setter Property="OverridesDefaultStyle" Value="true"/>
 <Setter Property="Template">
   <Setter.Value>
     <ControlTemplate TargetType="{x:Type local:MySeparator}">
     ...
     </ControlTemplate>
   </Setter.Value>
 <Setter/>
</Style>

But it does not work. In my target application I use the DLL library classes as follows (MainWindow.xaml):

<lib:MyMenu>
  <lib:MyMenuItem Header="Item 1"/>
  <lib:MySeparator/>
  <lib:MyMenuItem Header="Item 2"/>
</lib:MyMenu>

So my question is: how to realize a derived menu Separator stylized via Generic.xaml?

Upvotes: 1

Views: 557

Answers (1)

brunnerh
brunnerh

Reputation: 184727

You should not need a new subclass of Separator, and you can alternatively style the Separators that appear in your menu by embedding a Style in the menu's Style's Resources.

Upvotes: 2

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