CODEWITHSUNDEEP
javascriptregex
Kizz
Kizz

Reputation: 799

How to remove extra decimal points?

I need to alter users input and leave in the box only integer or decimal values, i.e. 4567 or 354.5635. I use the following statement:

v = v.replace(/[^\d\.]+/g, "");

But this allows multiple decimal points such as 345.45.345.67. How do I ensure that only one point is there?

Upvotes: 0

Views: 5487

Answers (5)

Shreya
Shreya

Reputation: 21

v = v.replace(/[A-Za-z$-]/g, ""); 
     // This will replace the alphabets

v = v.replace(/[^\d]*(\d+(\.\d+)?)?.*/g, "$1"); 
    // This will replace other then decimal

Upvotes: 1

user557597
user557597

Reputation:

Not sure if JS can do lookahead assertions, but if it can it could be done with a regex IF JS can also do reverse(input_string).

A reverse is needed because you want to allow the FIRST dot, and take out the rest.
However, search progresses left to right.

/(?:[.](?=.*[.])|[^\d.])+/g will take out all but the last '.'
So, the string has to be reversed, substituted, then reversed again.

Perl code example:

my $ss = 'asdf45.980.765';
$ss = reverse $ss;
$ss =~ s/(?:[.](?=.*[.])|[^\d.])+//g;
$ss = reverse $ss;
print $ss;

Output: 45.980765

Upvotes: 2

Ernest
Ernest

Reputation: 590

v = parseFloat(v).toFixed(numberOfDecimalDigits);

Upvotes: 4

Eugene
Eugene

Reputation: 3375

v = v.replace(/[^\d]*(\d+(\.\d+)?)?.*/g, "$1");

Upvotes: -1

yko
yko

Reputation: 2710

I'd recommend to use parseFloat here:

v = parseFloat(v);

This will guarantee you to have integer/decimal value or NaN.

Upvotes: 0

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