CODEWITHSUNDEEP
javaexceptioninteger
SonneXo
SonneXo

Reputation: 177

Integer.Parse(String) throws exception

I'm new at android developement, new to Java too. Originally, I'm a C# and C++ programmer, so this is kind of suspect to me. I wrote this code

String[] teile = temp.split(" ");

int[] teileInt = new int[] 
{
    50, 50, 50, 50, 50, 50
} ;

for (int i = 0; i < teile.length; ++i) {
    try {
        Integer integer = new Integer(teile[i]);
        //int d = Integer.parseInt(teile[i]);
    }
    catch (NumberFormatException ex)
    {
        Toast.makeText(this, teile[i] + getMessagesFromException(ex), Toast.LENGTH_SHORT).show();
    }
    //

}

Both expressions turn into the same Exception!

(Cant post an image)

The Toast says:

40null Invalid int: "40"
java.lang.NumberFormatException: Invalid
int: "40"

Im sorry, but I can' t figure out whats wrong... Is 40 not an Integer?

Upvotes: 1

Views: 435

Answers (1)

peter.petrov
peter.petrov

Reputation: 39457

Try this. Integer integer = new Integer(teile[i].trim());
I assume you have a leading or a trailing space in teile[i].

Upvotes: 2

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