CODEWITHSUNDEEP
hardwarechisel
Vikas Chauhan
Vikas Chauhan

Reputation: 31

It should unroll loop but instead it's throwing AssertionError

I was trying to genrating verilog for the below program but it's throwing AssertionError. Is the corresponding verilog unroll "io.opcode := io.a + io.b" statement 5 times ? it would be very helpful if someone can tell how for loop is working.

 val io = new Bundle {

    val a = UInt(INPUT, 2)
    val b = UInt(INPUT, 2)
    val opcode = UInt(INPUT, 2)
    val output = UInt(OUTPUT, 2)
  }

  for(j <- 0 to 4){

    io.opcode := io.a + io.b
  }

  io.output := io.opcode

Upvotes: 1

Views: 94

Answers (2)

Chris
Chris

Reputation: 3987

First, you "io.opcode" as an input, but you are assigning io.a + io.b to it.

Second, your for loop is doing nothing. It's scala code, and you aren't using the "j" iterator variable anywhere, so this is what it expands to:

io.opcode := io.a + io.b
io.opcode := io.a + io.b
io.opcode := io.a + io.b
io.opcode := io.a + io.b

The semantics here is that the last writer wins, so the last statement of "io.opcode = io.a + io.b" would be the final value. In fact, the previous three statements mean nothing, so they would be pruned from the graph. Of course, io.opcode is actually an input so it won't generate the code you want (it should throw an error).

Upvotes: 2

colins
colins

Reputation: 351

The io.opcode field is an input so when you assign to it you receive an error.

Upvotes: 2

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