CODEWITHSUNDEEP
makefilewildcard
user3599444
user3599444

Reputation: 145

Makefile wildcard with variable inside

I am trying to get all the files inside each folder with Makefile:

Test = $(wildcard */)

install: all
  @for dir in $(TEST); do \
    echo $$dir; \
    echo $(wildcard $$dir); \
  done

First echo outputs correctly: folder1/ folder2/ folder3/ but when used with wildcard in second echo I am getting empty output (each folder contains many files). Any suggestions why this doesn't work and how to archive this?

Upvotes: 2

Views: 2015

Answers (1)

Tsyvarev
Tsyvarev

Reputation: 65928

$(wildcard) is make function, which is evaluated once while makefile is parsed.

dir is a shell variable, which exists only when receipt is evaluated (using shell).

Because make is unaware about shell variables, pattern in $(wildcard $$dir) is interpreted by make literally: $$dir.

If you want to output list of files in a directory pointed by dir variable, you should use shell utilities. E.g. ls $$dir.

Upvotes: 4

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